[填空题]
A force of 10.0 ± 0.2 N is applied to a masz vqht3.:px6ls of 2.0 ± 0.01 kg, causes* ) m/mk d5hy: *dk88hrveo0t5g rssing it to accelerate. What is the percen5ym kmd:vgs )8*ro85*/hd st0k re hsetage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using theq/btt j,4cfr9t+b ru, .f1 nr4w(hcsr formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19