[填空题]
The potential differeui5ra ,7tn+s -w3ag;q*at1 izjf8 7zr9x mf vyvxp wjokb (grp x9/ 2)8r1wg(tnce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and 5gsc/x7d 02xdu2i4q+ano i aa so the uncertainty is the smallest value which it can rd o0axaau4i+57s dn2g/xc i2 qecord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.