[填空题]
The potential differenua/q*pip7 hv6kgl77sfzxq . u ky.q(rik)g:,t+u 7eyce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the mvq v/ (138qukxeux9qqc8nt2smallest value whik8(uqv/u2 xcn 9 31qmt evxq8qch it can record, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.