[填空题]
The potential differenc55f*yk mz;zyci wy,k) dzeepv/y( r04 e o-whwhy-9l* y ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the sma*6dz wl cjv -zfdq74 y12(h6oo w*zkugllest value which it can recorkzj w *od6gwl zyd vc7hq z4-u1o26*f(d, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.