[填空题]
The potential differe;tbd9ca7svl 6 nce 6 ak(y zcvaj44($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the smallest value wpjdl c.+jyt3 r:w-r o(hich it can rt l cworj-(p:d +.y3rjecord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.