[填空题]
The potential differenccuibj)9 ex+(m3w /xb;h;h vn6;wm h5oj)a ggve ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the sm(q k 3qin- qvjzn4tnh3:71wo wallest value which it can rect31nqjhwnq:z -(o3nqivw7 k4ord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.
Post time 2024-8-21 21:38:19