[填空题]
The radius of a circle of wire iw vcyh,snyipw9( /rnc -y.00os measured to be 10.0 ±w9u8jk jj i y* wuky-1bc x/4ki/(0goq 0.5 cm. What is the percentage error in the area of the loop? % What is the percentage error in the circumference of the loop? %
参考答案: 空格1: 10.0
空格2: 5.0
本题详细解析: First calculate the percentage errg2 01c a-ac6wpd vs0wnf(ha;j or in the radius of the loop: $$ \frac{\Delta \mathrm{r}}{\mathrm{r}}=\frac{0.5}{10}=5 \% $$ The area of a circle is $A=\pi r^2$ and so the percentage error on the area of the loop will be twice the percentage error of the radius, $\Delta A=10 \%$.
Post time 2024-8-21 21:38:19