[填空题]
A force of 10.0 ± 0.2 N is adar5nzi)7,q/l/ dh xipplied to a mass of 2.0 ±q:d3r.0 op*xe/ erwas5 r2phk 0.01 kg, causing it to accelerate. Whrphs5p.waqdr/k0e or*e :23x at is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the formula(t z73vhzu twd9i :1vbuf e+5o: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19